Base | Representation |
---|---|
bin | 1100000011011… |
… | …11100110101111 |
3 | 21001021110011011 |
4 | 12001233212233 |
5 | 201341323211 |
6 | 14011210051 |
7 | 2335336516 |
oct | 601574657 |
9 | 231243134 |
10 | 101120431 |
11 | 52097305 |
12 | 29a46927 |
13 | 17c46799 |
14 | d60367d |
15 | 8d26921 |
hex | 606f9af |
101120431 has 2 divisors, whose sum is σ = 101120432. Its totient is φ = 101120430.
The previous prime is 101120429. The next prime is 101120479. The reversal of 101120431 is 134021101.
It is a weak prime.
It is an emirp because it is prime and its reverse (134021101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101120431 - 21 = 101120429 is a prime.
It is a super-2 number, since 2×1011204312 = 20450683131251522, which contains 22 as substring.
Together with 101120429, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101120231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560215 + 50560216.
It is an arithmetic number, because the mean of its divisors is an integer number (50560216).
Almost surely, 2101120431 is an apocalyptic number.
101120431 is a deficient number, since it is larger than the sum of its proper divisors (1).
101120431 is an equidigital number, since it uses as much as digits as its factorization.
101120431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 101120431 is about 10055.8655022827. The cubic root of 101120431 is about 465.8859757123.
Adding to 101120431 its reverse (134021101), we get a palindrome (235141532).
The spelling of 101120431 in words is "one hundred one million, one hundred twenty thousand, four hundred thirty-one".
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