1011210001141 has 2 divisors, whose sum is σ = 1011210001142. Its totient is φ = 1011210001140.

The previous prime is 1011210001121. The next prime is 1011210001169. The reversal of 1011210001141 is 1411000121101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 513838080625 + 497371920516 = 716825^2 + 705246^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011210001141 - 2⁷ = 1011210001013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011210001111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505605000570 + 505605000571.

It is an arithmetic number, because the mean of its divisors is an integer number (505605000571).

Almost surely, 2^{1011210001141} is an apocalyptic number.

It is an amenable number.

1011210001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011210001141 is an equidigital number, since it uses as much as digits as its factorization.

1011210001141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 1011210001141 its reverse (1411000121101), we get a palindrome (2422210122242).

The spelling of 1011210001141 in words is "one trillion, eleven billion, two hundred ten million, one thousand, one hundred forty-one".