1011213043301 has 2 divisors, whose sum is σ = 1011213043302. Its totient is φ = 1011213043300.

The previous prime is 1011213043297. The next prime is 1011213043303. The reversal of 1011213043301 is 1033403121101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 627248160100 + 383964883201 = 791990^2 + 619649^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011213043301 - 2² = 1011213043297 is a prime.

Together with 1011213043303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011213043303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505606521650 + 505606521651.

It is an arithmetic number, because the mean of its divisors is an integer number (505606521651).

Almost surely, 2^{1011213043301} is an apocalyptic number.

It is an amenable number.

1011213043301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011213043301 is an equidigital number, since it uses as much as digits as its factorization.

1011213043301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1011213043301 its reverse (1033403121101), we get a palindrome (2044616164402).

The spelling of 1011213043301 in words is "one trillion, eleven billion, two hundred thirteen million, forty-three thousand, three hundred one".