Base | Representation |
---|---|
bin | 1001001100100110111010… |
… | …1111101001101010101111 |
3 | 1022210201101101000122222201 |
4 | 2103021232233221222233 |
5 | 2311134302003444413 |
6 | 33301252520122331 |
7 | 2062404005166661 |
oct | 223115657515257 |
9 | 38721341018881 |
10 | 10112210999983 |
11 | 3249623537144 |
12 | 11739930063a7 |
13 | 584767738831 |
14 | 26d60dc14531 |
15 | 1280961cb9dd |
hex | 9326ebe9aaf |
10112210999983 has 2 divisors, whose sum is σ = 10112210999984. Its totient is φ = 10112210999982.
The previous prime is 10112210999981. The next prime is 10112210999993. The reversal of 10112210999983 is 38999901221101.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10112210999983 - 21 = 10112210999981 is a prime.
It is a super-2 number, since 2×101122109999832 (a number of 27 digits) contains 22 as substring.
Together with 10112210999981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10112210999981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056105499991 + 5056105499992.
It is an arithmetic number, because the mean of its divisors is an integer number (5056105499992).
Almost surely, 210112210999983 is an apocalyptic number.
10112210999983 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112210999983 is an equidigital number, since it uses as much as digits as its factorization.
10112210999983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 55.
The spelling of 10112210999983 in words is "ten trillion, one hundred twelve billion, two hundred ten million, nine hundred ninety-nine thousand, nine hundred eighty-three".
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