101122121002013 has 4 divisors (see below), whose sum is σ = 101127785807328. Its totient is φ = 101116456196700.

The previous prime is 101122121002009. The next prime is 101122121002037. The reversal of 101122121002013 is 310200121221101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101122121002013 - 2² = 101122121002009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101122121001982 and 101122121002000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101122121002613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2832375881 + ... + 2832411582.

It is an arithmetic number, because the mean of its divisors is an integer number (25281946451832).

Almost surely, 2^{101122121002013} is an apocalyptic number.

It is an amenable number.

101122121002013 is a deficient number, since it is larger than the sum of its proper divisors (5664805315).

101122121002013 is an equidigital number, since it uses as much as digits as its factorization.

101122121002013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5664805314.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 101122121002013 its reverse (310200121221101), we get a palindrome (411322242223114).

The spelling of 101122121002013 in words is "one hundred one trillion, one hundred twenty-two billion, one hundred twenty-one million, two thousand, thirteen".