10112220191 has 2 divisors, whose sum is σ = 10112220192. Its totient is φ = 10112220190.

The previous prime is 10112220169. The next prime is 10112220193. The reversal of 10112220191 is 19102221101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10112220191 is a prime.

Together with 10112220193, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112220193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056110095 + 5056110096.

It is an arithmetic number, because the mean of its divisors is an integer number (5056110096).

Almost surely, 2^10112220191 is an apocalyptic number.

10112220191 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112220191 is an equidigital number, since it uses as much as digits as its factorization.

10112220191 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 10112220191 its reverse (19102221101), we get a palindrome (29214441292).

The spelling of 10112220191 in words is "ten billion, one hundred twelve million, two hundred twenty thousand, one hundred ninety-one".