Base | Representation |
---|---|
bin | 111100010001100… |
… | …010101010111100 |
3 | 2121110210212201120 |
4 | 330101202222330 |
5 | 4032333401140 |
6 | 244202110540 |
7 | 34026216363 |
oct | 7421425274 |
9 | 2543725646 |
10 | 1011231420 |
11 | 4798a5151 |
12 | 2427ab450 |
13 | 1316703b4 |
14 | 984327da |
15 | 5db9e1d0 |
hex | 3c462abc |
1011231420 has 24 divisors (see below), whose sum is σ = 2831448144. Its totient is φ = 269661696.
The previous prime is 1011231391. The next prime is 1011231437. The reversal of 1011231420 is 241321101.
1011231420 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×10112314203 (a number of 28 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1011231420.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8426869 + ... + 8426988.
It is an arithmetic number, because the mean of its divisors is an integer number (117977006).
Almost surely, 21011231420 is an apocalyptic number.
1011231420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1011231420 is an abundant number, since it is smaller than the sum of its proper divisors (1820216724).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1011231420 is a wasteful number, since it uses less digits than its factorization.
1011231420 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16853869 (or 16853867 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
The square root of 1011231420 is about 31799.8650940535. The cubic root of 1011231420 is about 1003.7298773847.
Adding to 1011231420 its reverse (241321101), we get a palindrome (1252552521).
It can be divided in two parts, 10 and 11231420, that added together give a triangular number (11231430 = T4739).
The spelling of 1011231420 in words is "one billion, eleven million, two hundred thirty-one thousand, four hundred twenty".
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