Base | Representation |
---|---|
bin | 1001001100100111010011… |
… | …1001110000011101101011 |
3 | 1022210201122120102111012021 |
4 | 2103021310321300131223 |
5 | 2311140004431000210 |
6 | 33301311050325311 |
7 | 2062406401266550 |
oct | 223116471603553 |
9 | 38721576374167 |
10 | 10112314312555 |
11 | 3249676890434 |
12 | 1173a01729837 |
13 | 584782c6c030 |
14 | 26d61d828a27 |
15 | 1280a02d7bda |
hex | 93274e7076b |
10112314312555 has 64 divisors (see below), whose sum is σ = 14979874452480. Its totient is φ = 6381605481984.
The previous prime is 10112314312543. The next prime is 10112314312559. The reversal of 10112314312555 is 55521341321101.
It is a cyclic number.
It is not a de Polignac number, because 10112314312555 - 217 = 10112314181483 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10112314312555.
It is not an unprimeable number, because it can be changed into a prime (10112314312559) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 210171841 + ... + 210219949.
It is an arithmetic number, because the mean of its divisors is an integer number (234060538320).
Almost surely, 210112314312555 is an apocalyptic number.
10112314312555 is a deficient number, since it is larger than the sum of its proper divisors (4867560139925).
10112314312555 is a wasteful number, since it uses less digits than its factorization.
10112314312555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49508.
The product of its (nonzero) digits is 18000, while the sum is 34.
Adding to 10112314312555 its reverse (55521341321101), we get a palindrome (65633655633656).
The spelling of 10112314312555 in words is "ten trillion, one hundred twelve billion, three hundred fourteen million, three hundred twelve thousand, five hundred fifty-five".
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