Base | Representation |
---|---|
bin | 1001001100100111101010… |
… | …1111010101010110001111 |
3 | 1022210201220101200212222111 |
4 | 2103021322233111112033 |
5 | 2311140210013241333 |
6 | 33301324505324451 |
7 | 2062412000553214 |
oct | 223117257252617 |
9 | 38721811625874 |
10 | 10112412243343 |
11 | 3249717099273 |
12 | 1173a2a496727 |
13 | 58479a339a47 |
14 | 26d62c83bb0b |
15 | 1280a8bce4cd |
hex | 9327abd558f |
10112412243343 has 2 divisors, whose sum is σ = 10112412243344. Its totient is φ = 10112412243342.
The previous prime is 10112412243331. The next prime is 10112412243431. The reversal of 10112412243343 is 34334221421101.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10112412243343 - 237 = 9974973289871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10112412943343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056206121671 + 5056206121672.
It is an arithmetic number, because the mean of its divisors is an integer number (5056206121672).
Almost surely, 210112412243343 is an apocalyptic number.
10112412243343 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112412243343 is an equidigital number, since it uses as much as digits as its factorization.
10112412243343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 10112412243343 its reverse (34334221421101), we get a palindrome (44446633664444).
The spelling of 10112412243343 in words is "ten trillion, one hundred twelve billion, four hundred twelve million, two hundred forty-three thousand, three hundred forty-three".
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