10112412243431 has 2 divisors, whose sum is σ = 10112412243432. Its totient is φ = 10112412243430.

The previous prime is 10112412243343. The next prime is 10112412243433. The reversal of 10112412243431 is 13434221421101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10112412243431 - 2²² = 10112408049127 is a prime.

It is a super-2 number, since 2×10112412243431² (a number of 27 digits) contains 22 as substring.

Together with 10112412243433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10112412243394 and 10112412243403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112412243433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056206121715 + 5056206121716.

It is an arithmetic number, because the mean of its divisors is an integer number (5056206121716).

Almost surely, 2^{10112412243431} is an apocalyptic number.

10112412243431 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112412243431 is an equidigital number, since it uses as much as digits as its factorization.

10112412243431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 10112412243431 its reverse (13434221421101), we get a palindrome (23546633664532).

The spelling of 10112412243431 in words is "ten trillion, one hundred twelve billion, four hundred twelve million, two hundred forty-three thousand, four hundred thirty-one".