Base | Representation |
---|---|
bin | 11101011011100101101… |
… | …11010001000100101011 |
3 | 10120200012100202101101210 |
4 | 32231302313101010223 |
5 | 113032012031430120 |
6 | 2052320445044203 |
7 | 133026402422004 |
oct | 16556267210453 |
9 | 3520170671353 |
10 | 1011244405035 |
11 | 35a959115917 |
12 | 143b9b856663 |
13 | 7448aa27047 |
14 | 36d319781ab |
15 | 1b4889d1ce0 |
hex | eb72dd112b |
1011244405035 has 128 divisors (see below), whose sum is σ = 1781615886336. Its totient is φ = 488340357120.
The previous prime is 1011244405027. The next prime is 1011244405049. The reversal of 1011244405035 is 5305044421101.
It is not a de Polignac number, because 1011244405035 - 23 = 1011244405027 is a prime.
It is a super-2 number, since 2×10112444050352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1011244404993 and 1011244405011.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 71809195 + ... + 71823275.
It is an arithmetic number, because the mean of its divisors is an integer number (13918874112).
Almost surely, 21011244405035 is an apocalyptic number.
1011244405035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1011244405035 is a deficient number, since it is larger than the sum of its proper divisors (770371481301).
1011244405035 is a wasteful number, since it uses less digits than its factorization.
1011244405035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14305.
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 1011244405035 its reverse (5305044421101), we get a palindrome (6316288826136).
The spelling of 1011244405035 in words is "one trillion, eleven billion, two hundred forty-four million, four hundred five thousand, thirty-five".
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