1011252311 has 2 divisors, whose sum is σ = 1011252312. Its totient is φ = 1011252310.

The previous prime is 1011252233. The next prime is 1011252313. The reversal of 1011252311 is 1132521101.

It is a strong prime.

It is an emirp because it is prime and its reverse (1132521101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011252311 is a prime.

Together with 1011252313, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1011252311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011252313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505626155 + 505626156.

It is an arithmetic number, because the mean of its divisors is an integer number (505626156).

Almost surely, 2^1011252311 is an apocalyptic number.

1011252311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011252311 is an equidigital number, since it uses as much as digits as its factorization.

1011252311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 1011252311 is about 31800.1935685933. The cubic root of 1011252311 is about 1003.7367893457.

Adding to 1011252311 its reverse (1132521101), we get a palindrome (2143773412).

The spelling of 1011252311 in words is "one billion, eleven million, two hundred fifty-two thousand, three hundred eleven".