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101130317 is a prime number
BaseRepresentation
bin1100000011100…
…10000001001101
321001021221201022
412001302001031
5201342132232
614011323525
72335410401
oct601620115
9231257638
10101130317
11520a3782
1229a505a5
1317c4b132
14d607101
158d29812
hex607204d

101130317 has 2 divisors, whose sum is σ = 101130318. Its totient is φ = 101130316.

The previous prime is 101130299. The next prime is 101130329. The reversal of 101130317 is 713031101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100380361 + 749956 = 10019^2 + 866^2 .

It is a cyclic number.

It is not a de Polignac number, because 101130317 - 220 = 100081741 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101130295 and 101130304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101130017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565158 + 50565159.

It is an arithmetic number, because the mean of its divisors is an integer number (50565159).

Almost surely, 2101130317 is an apocalyptic number.

It is an amenable number.

101130317 is a deficient number, since it is larger than the sum of its proper divisors (1).

101130317 is an equidigital number, since it uses as much as digits as its factorization.

101130317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63, while the sum is 17.

The square root of 101130317 is about 10056.3570441786. The cubic root of 101130317 is about 465.9011576052.

Adding to 101130317 its reverse (713031101), we get a palindrome (814161418).

The spelling of 101130317 in words is "one hundred one million, one hundred thirty thousand, three hundred seventeen".