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101131014014 = 252619611387
BaseRepresentation
bin101111000101111100…
…0001100111101111110
3100200000222211210210122
41132023320030331332
53124104014422024
6114243044334542
710210056302312
oct1361370147576
9320028753718
10101131014014
1139986903728
12177246a4452
1396c8c2bac4
144c75353b42
15296d699d5e
hex178be0cf7e

101131014014 has 8 divisors (see below), whose sum is σ = 151725370968. Its totient is φ = 50555890360.

The previous prime is 101131014011. The next prime is 101131014029. The reversal of 101131014014 is 410410131101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101131013983 and 101131014001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101131014011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4795172 + ... + 4816215.

It is an arithmetic number, because the mean of its divisors is an integer number (18965671371).

Almost surely, 2101131014014 is an apocalyptic number.

101131014014 is a deficient number, since it is larger than the sum of its proper divisors (50594356954).

101131014014 is an equidigital number, since it uses as much as digits as its factorization.

101131014014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9616650.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 101131014014 its reverse (410410131101), we get a palindrome (511541145115).

The spelling of 101131014014 in words is "one hundred one billion, one hundred thirty-one million, fourteen thousand, fourteen".

Divisors: 1 2 5261 10522 9611387 19222774 50565507007 101131014014