Base | Representation |
---|---|
bin | 10010110101100101… |
… | …11001001101010011 |
3 | 222002210211002101110 |
4 | 21122302321031103 |
5 | 131202441204210 |
6 | 4351305304403 |
7 | 505420666416 |
oct | 113262711523 |
9 | 28083732343 |
10 | 10113225555 |
11 | 431a71a054 |
12 | 1b62a95103 |
13 | c522b1a44 |
14 | 6bd1d7b7d |
15 | 3e2cc6420 |
hex | 25acb9353 |
10113225555 has 16 divisors (see below), whose sum is σ = 16422672384. Its totient is φ = 5313216480.
The previous prime is 10113225547. The next prime is 10113225607. The reversal of 10113225555 is 55552231101.
10113225555 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10113225555 - 23 = 10113225547 is a prime.
It is a super-2 number, since 2×101132255552 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5030451 + ... + 5032460.
It is an arithmetic number, because the mean of its divisors is an integer number (1026417024).
Almost surely, 210113225555 is an apocalyptic number.
10113225555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10113225555 is a deficient number, since it is larger than the sum of its proper divisors (6309446829).
10113225555 is a wasteful number, since it uses less digits than its factorization.
10113225555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10062986.
The product of its (nonzero) digits is 7500, while the sum is 30.
Adding to 10113225555 its reverse (55552231101), we get a palindrome (65665456656).
The spelling of 10113225555 in words is "ten billion, one hundred thirteen million, two hundred twenty-five thousand, five hundred fifty-five".
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