Base | Representation |
---|---|
bin | 10110111111101011100011… |
… | …010101110100101100010100 |
3 | 111021002020020121101220012010 |
4 | 112333223203111310230110 |
5 | 101223431104202204000 |
6 | 555031524454224220 |
7 | 30205424563111656 |
oct | 2677534325645424 |
9 | 437066217356163 |
10 | 101133114100500 |
11 | 2a251349413a79 |
12 | b414337355070 |
13 | 4457a7250a411 |
14 | 1ad8c2414c6d6 |
15 | ba5a8747ad50 |
hex | 5bfae3574b14 |
101133114100500 has 96 divisors (see below), whose sum is σ = 294510649200768. Its totient is φ = 26967821184000.
The previous prime is 101133114100489. The next prime is 101133114100517. The reversal of 101133114100500 is 5001411331101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 39268452 + ... + 41764548.
It is an arithmetic number, because the mean of its divisors is an integer number (3067819262508).
Almost surely, 2101133114100500 is an apocalyptic number.
101133114100500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
101133114100500 is an abundant number, since it is smaller than the sum of its proper divisors (193377535100268).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
101133114100500 is a wasteful number, since it uses less digits than its factorization.
101133114100500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2523130 (or 2523118 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 21.
Adding to 101133114100500 its reverse (5001411331101), we get a palindrome (106134525431601).
The spelling of 101133114100500 in words is "one hundred one trillion, one hundred thirty-three billion, one hundred fourteen million, one hundred thousand, five hundred".
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