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10113312104 = 2371727738351
BaseRepresentation
bin10010110101100110…
…01110010101101000
3222002210222111002222
421122303032111220
5131203001441404
64351311213212
7505421506640
oct113263162550
928083874088
1010113312104
11431a779085
121b62b17208
13c5231225c
146bd21b520
153e2ce1dbe
hex25acce568

10113312104 has 64 divisors (see below), whose sum is σ = 23029608960. Its totient is φ = 4064486400.

The previous prime is 10113312101. The next prime is 10113312137. The reversal of 10113312104 is 40121331101.

10113312104 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is not an unprimeable number, because it can be changed into a prime (10113312101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 244529 + ... + 282879.

It is an arithmetic number, because the mean of its divisors is an integer number (359837640).

Almost surely, 210113312104 is an apocalyptic number.

10113312104 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10113312104, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (11514804480).

10113312104 is an abundant number, since it is smaller than the sum of its proper divisors (12916296856).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10113312104 is a wasteful number, since it uses less digits than its factorization.

10113312104 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38658 (or 38654 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10113312104 its reverse (40121331101), we get a palindrome (50234643205).

The spelling of 10113312104 in words is "ten billion, one hundred thirteen million, three hundred twelve thousand, one hundred four".

Divisors: 1 2 4 7 8 14 17 28 34 56 68 119 136 238 277 476 554 952 1108 1939 2216 3878 4709 7756 9418 15512 18836 32963 37672 38351 65926 76702 131852 153404 263704 268457 306808 536914 651967 1073828 1303934 2147656 2607868 4563769 5215736 9127538 10623227 18255076 21246454 36510152 42492908 74362589 84985816 148725178 180594859 297450356 361189718 594900712 722379436 1264164013 1444758872 2528328026 5056656052 10113312104