101133301113 has 40 divisors (see below), whose sum is σ = 164307910536. Its totient is φ = 61619616000.

The previous prime is 101133301079. The next prime is 101133301141. The reversal of 101133301113 is 311103331101.

It can be written as a sum of positive squares in 4 ways, for example, as 4230591849 + 96902709264 = 65043^2 + 311292^2 .

It is not a de Polignac number, because 101133301113 - 2⁸ = 101133300857 is a prime.

It is not an unprimeable number, because it can be changed into a prime (101133301153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 369108 + ... + 581813.

Almost surely, 2^101133301113 is an apocalyptic number.

101133301113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

101133301113 is a deficient number, since it is larger than the sum of its proper divisors (63174609423).

101133301113 is a wasteful number, since it uses less digits than its factorization.

101133301113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 951047 (or 951038 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 101133301113 its reverse (311103331101), we get a palindrome (412236632214).

The spelling of 101133301113 in words is "one hundred one billion, one hundred thirty-three million, three hundred one thousand, one hundred thirteen".