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10113402151 = 23659667243
BaseRepresentation
bin10010110101100111…
…00100010100100111
3222002211011001122001
421122303210110213
5131203012332101
64351313150131
7505422333316
oct113263442447
928084131561
1010113402151
11431a82a7a6
121b62b5b347
13c52344238
146bd24227d
153e2d0d901
hex25ace4527

10113402151 has 8 divisors (see below), whose sum is σ = 10569144960. Its totient is φ = 9658995192.

The previous prime is 10113402127. The next prime is 10113402179. The reversal of 10113402151 is 15120431101.

10113402151 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10113402151 - 217 = 10113271079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113402181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 318465 + ... + 348778.

It is an arithmetic number, because the mean of its divisors is an integer number (1321143120).

Almost surely, 210113402151 is an apocalyptic number.

10113402151 is a deficient number, since it is larger than the sum of its proper divisors (455742809).

10113402151 is an equidigital number, since it uses as much as digits as its factorization.

10113402151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 667925.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 10113402151 its reverse (15120431101), we get a palindrome (25233833252).

The spelling of 10113402151 in words is "ten billion, one hundred thirteen million, four hundred two thousand, one hundred fifty-one".

Divisors: 1 23 659 15157 667243 15346589 439713137 10113402151