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10113433431 = 323146571499
BaseRepresentation
bin10010110101100111…
…01011111101010111
3222002211012122112120
421122303223331113
5131203014332211
64351313551023
7505422523443
oct113263537527
928084178476
1010113433431
11431a851252
121b62b75473
13c5235554a
146bd24d823
153e2d17d06
hex25acebf57

10113433431 has 8 divisors (see below), whose sum is σ = 14070864000. Its totient is φ = 6449145912.

The previous prime is 10113433403. The next prime is 10113433513. The reversal of 10113433431 is 13433431101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10113433431 - 29 = 10113432919 is a prime.

It is a super-2 number, since 2×101134334312 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113453431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73285681 + ... + 73285818.

It is an arithmetic number, because the mean of its divisors is an integer number (1758858000).

Almost surely, 210113433431 is an apocalyptic number.

10113433431 is a deficient number, since it is larger than the sum of its proper divisors (3957430569).

10113433431 is a wasteful number, since it uses less digits than its factorization.

10113433431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 146571525.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 10113433431 its reverse (13433431101), we get a palindrome (23546864532).

It can be divided in two parts, 101 and 13433431, that multiplied together give a palindrome (1356776531).

The spelling of 10113433431 in words is "ten billion, one hundred thirteen million, four hundred thirty-three thousand, four hundred thirty-one".

Divisors: 1 3 23 69 146571499 439714497 3371144477 10113433431