10114003140403 has 2 divisors, whose sum is σ = 10114003140404. Its totient is φ = 10114003140402.

The previous prime is 10114003140401. The next prime is 10114003140443. The reversal of 10114003140403 is 30404130041101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10114003140403 - 2¹ = 10114003140401 is a prime.

It is a super-2 number, since 2×10114003140403² (a number of 27 digits) contains 22 as substring.

Together with 10114003140401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (10114003140401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057001570201 + 5057001570202.

It is an arithmetic number, because the mean of its divisors is an integer number (5057001570202).

Almost surely, 2^{10114003140403} is an apocalyptic number.

10114003140403 is a deficient number, since it is larger than the sum of its proper divisors (1).

10114003140403 is an equidigital number, since it uses as much as digits as its factorization.

10114003140403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 10114003140403 its reverse (30404130041101), we get a palindrome (40518133181504).

The spelling of 10114003140403 in words is "ten trillion, one hundred fourteen billion, three million, one hundred forty thousand, four hundred three".