Base | Representation |
---|---|
bin | 11101011011111000101… |
… | …00110110011001100000 |
3 | 10120200121102110201110121 |
4 | 32231330110312121200 |
5 | 113032323201430130 |
6 | 2052344315410024 |
7 | 133033340654005 |
oct | 16557424663140 |
9 | 3520542421417 |
10 | 1011403155040 |
11 | 35aa2a794073 |
12 | 144024a53914 |
13 | 744b489a865 |
14 | 36d48a9d8ac |
15 | 1b4978ddd7a |
hex | eb7c536660 |
1011403155040 has 24 divisors (see below), whose sum is σ = 2389439954160. Its totient is φ = 404561261952.
The previous prime is 1011403155031. The next prime is 1011403155053. The reversal of 1011403155040 is 405513041101.
It is a junction number, because it is equal to n+sod(n) for n = 1011403154996 and 1011403155014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3160634700 + ... + 3160635019.
It is an arithmetic number, because the mean of its divisors is an integer number (99559998090).
Almost surely, 21011403155040 is an apocalyptic number.
1011403155040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1011403155040 is an abundant number, since it is smaller than the sum of its proper divisors (1378036799120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1011403155040 is an equidigital number, since it uses as much as digits as its factorization.
1011403155040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6321269734 (or 6321269726 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 1011403155040 its reverse (405513041101), we get a palindrome (1416916196141).
The spelling of 1011403155040 in words is "one trillion, eleven billion, four hundred three million, one hundred fifty-five thousand, forty".
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