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10120000133 is a prime number
BaseRepresentation
bin10010110110011001…
…01111001010000101
3222010021120021100202
421123030233022011
5131211210001013
64352110420245
7505532403365
oct113314571205
928107507322
1010120000133
114323526981
121b65201685
13c53814479
146c007c9a5
153e36b3858
hex25b32f285

10120000133 has 2 divisors, whose sum is σ = 10120000134. Its totient is φ = 10120000132.

The previous prime is 10120000117. The next prime is 10120000139. The reversal of 10120000133 is 33100002101.

10120000133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8859892129 + 1260108004 = 94127^2 + 35498^2 .

It is an emirp because it is prime and its reverse (33100002101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10120000133 - 24 = 10120000117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10120000139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060000066 + 5060000067.

It is an arithmetic number, because the mean of its divisors is an integer number (5060000067).

Almost surely, 210120000133 is an apocalyptic number.

It is an amenable number.

10120000133 is a deficient number, since it is larger than the sum of its proper divisors (1).

10120000133 is an equidigital number, since it uses as much as digits as its factorization.

10120000133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 10120000133 its reverse (33100002101), we get a palindrome (43220002234).

The spelling of 10120000133 in words is "ten billion, one hundred twenty million, one hundred thirty-three", and thus it is an aban number.