Base | Representation |
---|---|
bin | 11101011101000000111… |
… | …11110100100111110001 |
3 | 10120202011201101012111202 |
4 | 32232200133310213301 |
5 | 113040044030323441 |
6 | 2052524434420545 |
7 | 133054360106504 |
oct | 16564037644761 |
9 | 3522151335452 |
10 | 1012010011121 |
11 | 3602112a501a |
12 | 144174131755 |
13 | 74580526cb5 |
14 | 36da550d13b |
15 | 1b4d0d1319b |
hex | eba07f49f1 |
1012010011121 has 2 divisors, whose sum is σ = 1012010011122. Its totient is φ = 1012010011120.
The previous prime is 1012010011097. The next prime is 1012010011163. The reversal of 1012010011121 is 1211100102101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 862225530721 + 149784480400 = 928561^2 + 387020^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1012010011121 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1012010011171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506005005560 + 506005005561.
It is an arithmetic number, because the mean of its divisors is an integer number (506005005561).
Almost surely, 21012010011121 is an apocalyptic number.
It is an amenable number.
1012010011121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012010011121 is an equidigital number, since it uses as much as digits as its factorization.
1012010011121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 1012010011121 its reverse (1211100102101), we get a palindrome (2223110113222).
The spelling of 1012010011121 in words is "one trillion, twelve billion, ten million, eleven thousand, one hundred twenty-one".
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