101201211000211 has 24 divisors (see below), whose sum is σ = 119619974710464. Its totient is φ = 85352401330560.

The previous prime is 101201211000173. The next prime is 101201211000233. The reversal of 101201211000211 is 112000112102101.

It is a happy number.

It is not a de Polignac number, because 101201211000211 - 2¹⁵ = 101201210967443 is a prime.

It is a super-2 number, since 2×101201211000211² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101201211000191 and 101201211000200.

It is not an unprimeable number, because it can be changed into a prime (101201215000211) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 32095275 + ... + 35107108.

It is an arithmetic number, because the mean of its divisors is an integer number (4984165612936).

Almost surely, 2^{101201211000211} is an apocalyptic number.

101201211000211 is a deficient number, since it is larger than the sum of its proper divisors (18418763710253).

101201211000211 is an equidigital number, since it uses as much as digits as its factorization.

101201211000211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67202891 (or 67202884 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 101201211000211 its reverse (112000112102101), we get a palindrome (213201323102312).

The spelling of 101201211000211 in words is "one hundred one trillion, two hundred one billion, two hundred eleven million, two hundred eleven", and thus it is an aban number.