Base | Representation |
---|---|
bin | 101111001000000010… |
… | …1100001001001100101 |
3 | 100200012220200121222012 |
4 | 1132100011201021211 |
5 | 3124230103112123 |
6 | 114254045444005 |
7 | 10211604343415 |
oct | 1362005411145 |
9 | 320186617865 |
10 | 101201613413 |
11 | 39a1274403a |
12 | 17744270605 |
13 | 970a74a3b4 |
14 | 4c80890645 |
15 | 2974993378 |
hex | 1790161265 |
101201613413 has 2 divisors, whose sum is σ = 101201613414. Its totient is φ = 101201613412.
The previous prime is 101201613361. The next prime is 101201613431. The reversal of 101201613413 is 314316102101.
It is a happy number.
Together with next prime (101201613431) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100880558689 + 321054724 = 317617^2 + 17918^2 .
It is a cyclic number.
It is not a de Polignac number, because 101201613413 - 26 = 101201613349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101201613463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600806706 + 50600806707.
It is an arithmetic number, because the mean of its divisors is an integer number (50600806707).
Almost surely, 2101201613413 is an apocalyptic number.
It is an amenable number.
101201613413 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201613413 is an equidigital number, since it uses as much as digits as its factorization.
101201613413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 101201613413 its reverse (314316102101), we get a palindrome (415517715514).
The spelling of 101201613413 in words is "one hundred one billion, two hundred one million, six hundred thirteen thousand, four hundred thirteen".
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