10123020011213 has 4 divisors (see below), whose sum is σ = 10123051454880. Its totient is φ = 10122988567548.

The previous prime is 10123020011197. The next prime is 10123020011257. The reversal of 10123020011213 is 31211002032101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10123020011213 - 2⁴ = 10123020011197 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10123020011191 and 10123020011200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10123020011413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15233873 + ... + 15884486.

It is an arithmetic number, because the mean of its divisors is an integer number (2530762863720).

Almost surely, 2^{10123020011213} is an apocalyptic number.

It is an amenable number.

10123020011213 is a deficient number, since it is larger than the sum of its proper divisors (31443667).

10123020011213 is an equidigital number, since it uses as much as digits as its factorization.

10123020011213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31443666.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10123020011213 its reverse (31211002032101), we get a palindrome (41334022043314).

The spelling of 10123020011213 in words is "ten trillion, one hundred twenty-three billion, twenty million, eleven thousand, two hundred thirteen".