101253115303 has 4 divisors (see below), whose sum is σ = 105655424688. Its totient is φ = 96850805920.

The previous prime is 101253115297. The next prime is 101253115307. The reversal of 101253115303 is 303511352101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303511352101 = 9829 ⋅30879169.

It is a cyclic number.

It is not a de Polignac number, because 101253115303 - 2⁹ = 101253114791 is a prime.

It is a super-2 number, since 2×101253115303² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101253115307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2201154658 + ... + 2201154703.

It is an arithmetic number, because the mean of its divisors is an integer number (26413856172).

Almost surely, 2^101253115303 is an apocalyptic number.

101253115303 is a deficient number, since it is larger than the sum of its proper divisors (4402309385).

101253115303 is an equidigital number, since it uses as much as digits as its factorization.

101253115303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4402309384.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 101253115303 its reverse (303511352101), we get a palindrome (404764467404).

The spelling of 101253115303 in words is "one hundred one billion, two hundred fifty-three million, one hundred fifteen thousand, three hundred three".