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1013002022 = 2506501011
BaseRepresentation
bin111100011000010…
…010111100100110
32121121010211112102
4330120102330212
54033312031042
6244304052102
734050242444
oct7430227446
92547124472
101013002022
1147a8a445a
12243304032
13131b402a6
1498773b94
155ddedb32
hex3c612f26

1013002022 has 4 divisors (see below), whose sum is σ = 1519503036. Its totient is φ = 506501010.

The previous prime is 1013001961. The next prime is 1013002031. The reversal of 1013002022 is 2202003101.

It is a happy number.

1013002022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 2202003101 = 7333004097.

It is a junction number, because it is equal to n+sod(n) for n = 1013001994 and 1013002012.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 253250504 + ... + 253250507.

It is an arithmetic number, because the mean of its divisors is an integer number (379875759).

Almost surely, 21013002022 is an apocalyptic number.

1013002022 is a deficient number, since it is larger than the sum of its proper divisors (506501014).

1013002022 is an equidigital number, since it uses as much as digits as its factorization.

1013002022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 506501013.

The product of its (nonzero) digits is 24, while the sum is 11.

The square root of 1013002022 is about 31827.6926904857. The cubic root of 1013002022 is about 1004.3153582294.

Adding to 1013002022 its reverse (2202003101), we get a palindrome (3215005123).

The spelling of 1013002022 in words is "one billion, thirteen million, two thousand, twenty-two".

Divisors: 1 2 506501011 1013002022