1013101000013 has 4 divisors (see below), whose sum is σ = 1013103014688. Its totient is φ = 1013098985340.

The previous prime is 1013100999923. The next prime is 1013101000019. The reversal of 1013101000013 is 3100001013101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1013101000013 - 2¹⁶ = 1013100934477 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1013100999958 and 1013101000003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1013101000019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 443168 + ... + 1490838.

It is an arithmetic number, because the mean of its divisors is an integer number (253275753672).

Almost surely, 2^{1013101000013} is an apocalyptic number.

It is an amenable number.

1013101000013 is a deficient number, since it is larger than the sum of its proper divisors (2014675).

1013101000013 is an equidigital number, since it uses as much as digits as its factorization.

1013101000013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2014674.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 1013101000013 its reverse (3100001013101), we get a palindrome (4113102013114).

The spelling of 1013101000013 in words is "one trillion, thirteen billion, one hundred one million, thirteen", and thus it is an aban number.