Base | Representation |
---|---|
bin | 1001001101101110011100… |
… | …0110001001111011100111 |
3 | 1022212112221101101200000202 |
4 | 2103123213012021323213 |
5 | 2311443111432100112 |
6 | 33314145554101115 |
7 | 2063653533246164 |
oct | 223334706117347 |
9 | 38775841350022 |
10 | 10131410034407 |
11 | 3256785925942 |
12 | 117765087a79b |
13 | 5865071b2c2c |
14 | 27051199d06b |
15 | 12881b97e6c2 |
hex | 936e7189ee7 |
10131410034407 has 2 divisors, whose sum is σ = 10131410034408. Its totient is φ = 10131410034406.
The previous prime is 10131410034401. The next prime is 10131410034409. The reversal of 10131410034407 is 70443001413101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10131410034407 - 24 = 10131410034391 is a prime.
Together with 10131410034409, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10131410034407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10131410034401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065705017203 + 5065705017204.
It is an arithmetic number, because the mean of its divisors is an integer number (5065705017204).
Almost surely, 210131410034407 is an apocalyptic number.
10131410034407 is a deficient number, since it is larger than the sum of its proper divisors (1).
10131410034407 is an equidigital number, since it uses as much as digits as its factorization.
10131410034407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 10131410034407 its reverse (70443001413101), we get a palindrome (80574411447508).
The spelling of 10131410034407 in words is "ten trillion, one hundred thirty-one billion, four hundred ten million, thirty-four thousand, four hundred seven".
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