10131441181 has 2 divisors, whose sum is σ = 10131441182. Its totient is φ = 10131441180.

The previous prime is 10131441179. The next prime is 10131441209. The reversal of 10131441181 is 18114413101.

10131441181 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6098048100 + 4033393081 = 78090^2 + 63509^2 .

It is an emirp because it is prime and its reverse (18114413101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10131441181 - 2¹ = 10131441179 is a prime.

It is a super-2 number, since 2×10131441181² (a number of 21 digits) contains 22 as substring.

Together with 10131441179, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10131451181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065720590 + 5065720591.

It is an arithmetic number, because the mean of its divisors is an integer number (5065720591).

Almost surely, 2^10131441181 is an apocalyptic number.

It is an amenable number.

10131441181 is a deficient number, since it is larger than the sum of its proper divisors (1).

10131441181 is an equidigital number, since it uses as much as digits as its factorization.

10131441181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 25.

Adding to 10131441181 its reverse (18114413101), we get a palindrome (28245854282).

The spelling of 10131441181 in words is "ten billion, one hundred thirty-one million, four hundred forty-one thousand, one hundred eighty-one".