Base | Representation |
---|---|
bin | 11101011111010000000… |
… | …01011101011010100100 |
3 | 10120212021100101112021211 |
4 | 32233220001131122210 |
5 | 113100023230330200 |
6 | 2053243502521204 |
7 | 133126200665344 |
oct | 16575001353244 |
9 | 3525240345254 |
10 | 1013210011300 |
11 | 360777700a03 |
12 | 144449b96204 |
13 | 7471201b586 |
14 | 3707aa3cd24 |
15 | 1b55134daba |
hex | ebe805d6a4 |
1013210011300 has 144 divisors (see below), whose sum is σ = 2510297455680. Its totient is φ = 352553472000.
The previous prime is 1013210011273. The next prime is 1013210011309. The reversal of 1013210011300 is 31100123101.
1013210011300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×10132100113002 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1013210011309) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 941755 + ... + 1706845.
It is an arithmetic number, because the mean of its divisors is an integer number (17432621220).
Almost surely, 21013210011300 is an apocalyptic number.
1013210011300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1013210011300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1255148727840).
1013210011300 is an abundant number, since it is smaller than the sum of its proper divisors (1497087444380).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1013210011300 is a wasteful number, since it uses less digits than its factorization.
1013210011300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 765182 (or 765175 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1013210011300 its reverse (31100123101), we get a palindrome (1044310134401).
The spelling of 1013210011300 in words is "one trillion, thirteen billion, two hundred ten million, eleven thousand, three hundred".
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