Base | Representation |
---|---|
bin | 1001001101110101111001… |
… | …1110111000001101100111 |
3 | 1022212202002222100001221202 |
4 | 2103131132132320031213 |
5 | 2312011212212113020 |
6 | 33315120424433115 |
7 | 2064054264230111 |
oct | 223353636701547 |
9 | 38782088301852 |
10 | 10133413004135 |
11 | 3257613510723 |
12 | 1177b0b61879b |
13 | 586766159c15 |
14 | 2706619cc3b1 |
15 | 1288d772be75 |
hex | 9375e7b8367 |
10133413004135 has 32 divisors (see below), whose sum is σ = 12467426005440. Its totient is φ = 7902188236800.
The previous prime is 10133413004119. The next prime is 10133413004159. The reversal of 10133413004135 is 53140031433101.
It is a happy number.
It is not a de Polignac number, because 10133413004135 - 24 = 10133413004119 is a prime.
It is a super-2 number, since 2×101334130041352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10133413004098 and 10133413004107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1781226371 + ... + 1781232059.
It is an arithmetic number, because the mean of its divisors is an integer number (389607062670).
Almost surely, 210133413004135 is an apocalyptic number.
10133413004135 is a deficient number, since it is larger than the sum of its proper divisors (2334013001305).
10133413004135 is a wasteful number, since it uses less digits than its factorization.
10133413004135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11699.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 10133413004135 its reverse (53140031433101), we get a palindrome (63273444437236).
The spelling of 10133413004135 in words is "ten trillion, one hundred thirty-three billion, four hundred thirteen million, four thousand, one hundred thirty-five".
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