Base | Representation |
---|---|
bin | 11101011111101011110… |
… | …00000100110010000111 |
3 | 10120212212112201201201220 |
4 | 32233311320010302013 |
5 | 113101012230312020 |
6 | 2053322524251423 |
7 | 133135022353200 |
oct | 16576570046207 |
9 | 3525775651656 |
10 | 1013442432135 |
11 | 360886918141 |
12 | 1444b39a0b73 |
13 | 7474b2176b3 |
14 | 3709d8605a7 |
15 | 1b56695e240 |
hex | ebf5e04c87 |
1013442432135 has 96 divisors (see below), whose sum is σ = 1898161724160. Its totient is φ = 460364663808.
The previous prime is 1013442432113. The next prime is 1013442432137. The reversal of 1013442432135 is 5312342443101.
It is not a de Polignac number, because 1013442432135 - 211 = 1013442430087 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1013442432096 and 1013442432105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1013442432137) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 317991012 + ... + 317994198.
It is an arithmetic number, because the mean of its divisors is an integer number (19772517960).
Almost surely, 21013442432135 is an apocalyptic number.
1013442432135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1013442432135 is a deficient number, since it is larger than the sum of its proper divisors (884719292025).
1013442432135 is a wasteful number, since it uses less digits than its factorization.
1013442432135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5805 (or 5798 counting only the distinct ones).
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 1013442432135 its reverse (5312342443101), we get a palindrome (6325784875236).
The spelling of 1013442432135 in words is "one trillion, thirteen billion, four hundred forty-two million, four hundred thirty-two thousand, one hundred thirty-five".
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