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10135134431 is a prime number
BaseRepresentation
bin10010111000001100…
…11110000011011111
3222011100001011201022
421130012132003133
5131224043300211
64353411034355
7506105135612
oct113406360337
928140034638
1010135134431
114331023564
121b6a29b9bb
13c569b2c86
146c209c179
153e4ba2bdb
hex25c19e0df

10135134431 has 2 divisors, whose sum is σ = 10135134432. Its totient is φ = 10135134430.

The previous prime is 10135134353. The next prime is 10135134433. The reversal of 10135134431 is 13443153101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10135134431 - 230 = 9061392607 is a prime.

It is a super-2 number, since 2×101351344312 (a number of 21 digits) contains 22 as substring.

Together with 10135134433, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10135134431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10135134433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5067567215 + 5067567216.

It is an arithmetic number, because the mean of its divisors is an integer number (5067567216).

Almost surely, 210135134431 is an apocalyptic number.

10135134431 is a deficient number, since it is larger than the sum of its proper divisors (1).

10135134431 is an equidigital number, since it uses as much as digits as its factorization.

10135134431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 10135134431 its reverse (13443153101), we get a palindrome (23578287532).

The spelling of 10135134431 in words is "ten billion, one hundred thirty-five million, one hundred thirty-four thousand, four hundred thirty-one".