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101433230131 = 424323906017
BaseRepresentation
bin101111001110111100…
…1000100001100110011
3100200211001111222101011
41132131321010030303
53130213401331011
6114333042051351
710220416142002
oct1363571041463
9320731458334
10101433230131
113a021461112
12177a9949b57
1397467244cc
144ca3542c39
152989e95621
hex179de44333

101433230131 has 4 divisors (see below), whose sum is σ = 101457140392. Its totient is φ = 101409319872.

The previous prime is 101433230113. The next prime is 101433230153. The reversal of 101433230131 is 131032334101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101433230131 - 229 = 100896359219 is a prime.

It is a super-2 number, since 2×1014332301312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101433230831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11948766 + ... + 11957251.

It is an arithmetic number, because the mean of its divisors is an integer number (25364285098).

Almost surely, 2101433230131 is an apocalyptic number.

101433230131 is a deficient number, since it is larger than the sum of its proper divisors (23910261).

101433230131 is an equidigital number, since it uses as much as digits as its factorization.

101433230131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23910260.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 101433230131 its reverse (131032334101), we get a palindrome (232465564232).

The spelling of 101433230131 in words is "one hundred one billion, four hundred thirty-three million, two hundred thirty thousand, one hundred thirty-one".

Divisors: 1 4243 23906017 101433230131