1014341313000 has 64 divisors (see below), whose sum is σ = 3164744905920. Its totient is φ = 270491016000.

The previous prime is 1014341312987. The next prime is 1014341313049. The reversal of 1014341313000 is 3131434101.

It is a super-4 number, since 4×1014341313000⁴ (a number of 49 digits) contains 4444 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 169053886 + ... + 169059885.

It is an arithmetic number, because the mean of its divisors is an integer number (49449139155).

Almost surely, 2^{1014341313000} is an apocalyptic number.

1014341313000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1014341313000 is an abundant number, since it is smaller than the sum of its proper divisors (2150403592920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1014341313000 is a wasteful number, since it uses less digits than its factorization.

1014341313000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 338113795 (or 338113781 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1014341313000 its reverse (3131434101), we get a palindrome (1017472747101).

The spelling of 1014341313000 in words is "one trillion, fourteen billion, three hundred forty-one million, three hundred thirteen thousand".