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10144303121 = 17991602143
BaseRepresentation
bin10010111001010010…
…11100100000010001
3222011222021222210102
421130221130200101
5131233420144441
64354335342145
7506246103521
oct113451344021
928158258712
1010144303121
114336216097
121b71381955
13c58873334
146c33a7681
153e58b469b
hex25ca5c811

10144303121 has 8 divisors (see below), whose sum is σ = 10751883264. Its totient is φ = 9537929280.

The previous prime is 10144303067. The next prime is 10144303159. The reversal of 10144303121 is 12130344101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10144303121 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10144303093 and 10144303102.

It is not an unprimeable number, because it can be changed into a prime (10144303171) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 284225 + ... + 317918.

It is an arithmetic number, because the mean of its divisors is an integer number (1343985408).

Almost surely, 210144303121 is an apocalyptic number.

It is an amenable number.

10144303121 is a deficient number, since it is larger than the sum of its proper divisors (607580143).

10144303121 is an equidigital number, since it uses as much as digits as its factorization.

10144303121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 603151.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 10144303121 its reverse (12130344101), we get a palindrome (22274647222).

The spelling of 10144303121 in words is "ten billion, one hundred forty-four million, three hundred three thousand, one hundred twenty-one".

Divisors: 1 17 991 16847 602143 10236431 596723713 10144303121