10154313403 has 4 divisors (see below), whose sum is σ = 10935414448. Its totient is φ = 9373212360.

The previous prime is 10154313391. The next prime is 10154313419. The reversal of 10154313403 is 30431345101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10154313403 is a prime.

It is a super-2 number, since 2×10154313403² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10154313473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 390550503 + ... + 390550528.

It is an arithmetic number, because the mean of its divisors is an integer number (2733853612).

Almost surely, 2^10154313403 is an apocalyptic number.

10154313403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

10154313403 is a deficient number, since it is larger than the sum of its proper divisors (781101045).

10154313403 is an equidigital number, since it uses as much as digits as its factorization.

10154313403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 781101044.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 10154313403 its reverse (30431345101), we get a palindrome (40585658504).

The spelling of 10154313403 in words is "ten billion, one hundred fifty-four million, three hundred thirteen thousand, four hundred three".