Base | Representation |
---|---|
bin | 11101101100010001010… |
… | …10100100111110001111 |
3 | 10121112022111111102210220 |
4 | 32312020222210332033 |
5 | 113203332212041030 |
6 | 2100401245002423 |
7 | 133464336604620 |
oct | 16661052447617 |
9 | 3545274442726 |
10 | 1020200112015 |
11 | 363734404047 |
12 | 14587ab53413 |
13 | 75287269746 |
14 | 3754113da47 |
15 | 1b80ed5ea10 |
hex | ed88aa4f8f |
1020200112015 has 128 divisors (see below), whose sum is σ = 1984689838080. Its totient is φ = 436849459200.
The previous prime is 1020200111993. The next prime is 1020200112067. The reversal of 1020200112015 is 5102110020201.
It is not a de Polignac number, because 1020200112015 - 210 = 1020200110991 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a junction number, because it is equal to n+sod(n) for n = 1020200111985 and 1020200112003.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 449624301 + ... + 449626569.
It is an arithmetic number, because the mean of its divisors is an integer number (15505389360).
Almost surely, 21020200112015 is an apocalyptic number.
1020200112015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1020200112015 is a deficient number, since it is larger than the sum of its proper divisors (964489726065).
1020200112015 is a wasteful number, since it uses less digits than its factorization.
1020200112015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3393.
The product of its (nonzero) digits is 40, while the sum is 15.
Adding to 1020200112015 its reverse (5102110020201), we get a palindrome (6122310132216).
The spelling of 1020200112015 in words is "one trillion, twenty billion, two hundred million, one hundred twelve thousand, fifteen".
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