Base | Representation |
---|---|
bin | 101111100010111000… |
… | …0101011111000011111 |
3 | 100202112200011012112122 |
4 | 1133011300223320133 |
5 | 3133101120401030 |
6 | 114523254453155 |
7 | 10243120501055 |
oct | 1370560537037 |
9 | 322480135478 |
10 | 102102122015 |
11 | 3a334a93523 |
12 | 179559641bb |
13 | 982219141a |
14 | 4d283001d5 |
15 | 29c8a708e5 |
hex | 17c5c2be1f |
102102122015 has 4 divisors (see below), whose sum is σ = 122522546424. Its totient is φ = 81681697608.
The previous prime is 102102121997. The next prime is 102102122033. The reversal of 102102122015 is 510221201201.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (102102121997) and next prime (102102122033).
It is a cyclic number.
It is not a de Polignac number, because 102102122015 - 216 = 102102056479 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 102102121984 and 102102122002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10210212197 + ... + 10210212206.
It is an arithmetic number, because the mean of its divisors is an integer number (30630636606).
Almost surely, 2102102122015 is an apocalyptic number.
102102122015 is a deficient number, since it is larger than the sum of its proper divisors (20420424409).
102102122015 is an equidigital number, since it uses as much as digits as its factorization.
102102122015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20420424408.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 102102122015 its reverse (510221201201), we get a palindrome (612323323216).
The spelling of 102102122015 in words is "one hundred two billion, one hundred two million, one hundred twenty-two thousand, fifteen".
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