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1021115324135 = 5204223064827
BaseRepresentation
bin11101101101111110011…
…01110101011011100111
310121121200021122000211002
432312333031311123213
5113212221010333020
62101032141103515
7133526122021544
oct16667715653347
93547607560732
101021115324135
11364063a864a5
12145a95557b9b
13753a1a5b18a
14375ca8d9bcb
151b865393975
hexedbf3756e7

1021115324135 has 4 divisors (see below), whose sum is σ = 1225338388968. Its totient is φ = 816892259304.

The previous prime is 1021115324123. The next prime is 1021115324183. The reversal of 1021115324135 is 5314235111201.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1021115324135 - 236 = 952395847399 is a prime.

It is a super-2 number, since 2×10211153241352 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1021115324098 and 1021115324107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102111532409 + ... + 102111532418.

It is an arithmetic number, because the mean of its divisors is an integer number (306334597242).

Almost surely, 21021115324135 is an apocalyptic number.

1021115324135 is a deficient number, since it is larger than the sum of its proper divisors (204223064833).

1021115324135 is an equidigital number, since it uses as much as digits as its factorization.

1021115324135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 204223064832.

The product of its (nonzero) digits is 3600, while the sum is 29.

The spelling of 1021115324135 in words is "one trillion, twenty-one billion, one hundred fifteen million, three hundred twenty-four thousand, one hundred thirty-five".

Divisors: 1 5 204223064827 1021115324135