Base | Representation |
---|---|
bin | 10011000001010001… |
… | …01011100001001101 |
3 | 222100122012021121122 |
4 | 21200220223201031 |
5 | 131403032230331 |
6 | 4405125410325 |
7 | 511020602312 |
oct | 114050534115 |
9 | 28318167548 |
10 | 10211211341 |
11 | 436aa65241 |
12 | 1b8b8699a5 |
13 | c6969b7b6 |
14 | 6cc222d09 |
15 | 3eb6ce17b |
hex | 260a2b84d |
10211211341 has 2 divisors, whose sum is σ = 10211211342. Its totient is φ = 10211211340.
The previous prime is 10211211337. The next prime is 10211211343. The reversal of 10211211341 is 14311211201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7633516900 + 2577694441 = 87370^2 + 50771^2 .
It is a cyclic number.
It is not a de Polignac number, because 10211211341 - 22 = 10211211337 is a prime.
It is a super-3 number, since 3×102112113413 (a number of 31 digits) contains 333 as substring.
Together with 10211211343, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10211211343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105605670 + 5105605671.
It is an arithmetic number, because the mean of its divisors is an integer number (5105605671).
Almost surely, 210211211341 is an apocalyptic number.
It is an amenable number.
10211211341 is a deficient number, since it is larger than the sum of its proper divisors (1).
10211211341 is an equidigital number, since it uses as much as digits as its factorization.
10211211341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 10211211341 its reverse (14311211201), we get a palindrome (24522422542).
The spelling of 10211211341 in words is "ten billion, two hundred eleven million, two hundred eleven thousand, three hundred forty-one".
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