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10211232113 is a prime number
BaseRepresentation
bin10011000001010001…
…10000100101110001
3222100122020100002222
421200220300211301
5131403033411423
64405130050425
7511021020005
oct114050604561
928318210088
1010211232113
11436aa79905
121b8b879a15
13c696a80a4
146cc22a705
153eb6d53c8
hex260a30971

10211232113 has 2 divisors, whose sum is σ = 10211232114. Its totient is φ = 10211232112.

The previous prime is 10211232103. The next prime is 10211232127. The reversal of 10211232113 is 31123211201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9306846784 + 904385329 = 96472^2 + 30073^2 .

It is a cyclic number.

It is not a de Polignac number, because 10211232113 - 210 = 10211231089 is a prime.

It is a super-2 number, since 2×102112321132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10211232091 and 10211232100.

It is not a weakly prime, because it can be changed into another prime (10211232103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105616056 + 5105616057.

It is an arithmetic number, because the mean of its divisors is an integer number (5105616057).

Almost surely, 210211232113 is an apocalyptic number.

It is an amenable number.

10211232113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10211232113 is an equidigital number, since it uses as much as digits as its factorization.

10211232113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10211232113 its reverse (31123211201), we get a palindrome (41334443314).

The spelling of 10211232113 in words is "ten billion, two hundred eleven million, two hundred thirty-two thousand, one hundred thirteen".