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102113000000 = 2656119283
BaseRepresentation
bin101111100011001101…
…0001011101001000000
3100202120102121212022222
41133012122023221000
53133111412000000
6114524323550212
710243312115234
oct1370632135100
9322512555288
10102113000000
113a3401432a0
121795952b368
1398244cc7bb
144d299325c4
1529c99bda85
hex17c668ba40

102113000000 has 196 divisors, whose sum is σ = 276340525296. Its totient is φ = 37128000000.

The previous prime is 102112999993. The next prime is 102113000053. The reversal of 102113000000 is 311201.

It is a Harshad number since it is a multiple of its sum of digits (8).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 10995359 + ... + 11004641.

Almost surely, 2102113000000 is an apocalyptic number.

102113000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 102113000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (138170262648).

102113000000 is an abundant number, since it is smaller than the sum of its proper divisors (174227525296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

102113000000 is an frugal number, since it uses more digits than its factorization.

102113000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9336 (or 9301 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 8.

Adding to 102113000000 its reverse (311201), we get a palindrome (102113311201).

The spelling of 102113000000 in words is "one hundred two billion, one hundred thirteen million", and thus it is an aban number.