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10211443331142 = 2317100112189521
BaseRepresentation
bin1001010010011000100101…
…1100111101000001000110
31100011012112001011101120010
42110212021130331001012
52314301013443044032
633415023341251050
72102516041116624
oct224461134750106
940135461141503
1010211443331142
113287715604289
12118b067863a86
13590c201a5451
14274344d24514
1512a952d28ccc
hex9498973d046

10211443331142 has 16 divisors (see below), whose sum is σ = 21624232936752. Its totient is φ = 3203590064640.

The previous prime is 10211443331113. The next prime is 10211443331143. The reversal of 10211443331142 is 24113334411201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10211443331143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50056094659 + ... + 50056094862.

It is an arithmetic number, because the mean of its divisors is an integer number (1351514558547).

Almost surely, 210211443331142 is an apocalyptic number.

10211443331142 is an abundant number, since it is smaller than the sum of its proper divisors (11412789605610).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10211443331142 is a wasteful number, since it uses less digits than its factorization.

10211443331142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100112189543.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 10211443331142 its reverse (24113334411201), we get a palindrome (34324777742343).

The spelling of 10211443331142 in words is "ten trillion, two hundred eleven billion, four hundred forty-three million, three hundred thirty-one thousand, one hundred forty-two".

Divisors: 1 2 3 6 17 34 51 102 100112189521 200224379042 300336568563 600673137126 1701907221857 3403814443714 5105721665571 10211443331142