Base | Representation |
---|---|
bin | 1001010010011001010000… |
… | …1010110001001000010011 |
3 | 1100011012222120110021020011 |
4 | 2110212110022301020103 |
5 | 2314301401004110420 |
6 | 33415053242455351 |
7 | 2102523353206645 |
oct | 224462412611023 |
9 | 40135876407204 |
10 | 10211623113235 |
11 | 32877a8038225 |
12 | 118b0b7b04557 |
13 | 590c4b50109b |
14 | 274360b62895 |
15 | 12a9639dc95a |
hex | 949942b1213 |
10211623113235 has 24 divisors (see below), whose sum is σ = 12934429127280. Its totient is φ = 7738382530368.
The previous prime is 10211623113203. The next prime is 10211623113253. The reversal of 10211623113235 is 53231132611201.
It is not a de Polignac number, because 10211623113235 - 25 = 10211623113203 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10211623113197 and 10211623113206.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14491129 + ... + 15179461.
It is an arithmetic number, because the mean of its divisors is an integer number (538934546970).
Almost surely, 210211623113235 is an apocalyptic number.
10211623113235 is a deficient number, since it is larger than the sum of its proper divisors (2722806014045).
10211623113235 is an equidigital number, since it uses as much as digits as its factorization.
10211623113235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 696595 (or 696576 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 10211623113235 its reverse (53231132611201), we get a palindrome (63442755724436).
The spelling of 10211623113235 in words is "ten trillion, two hundred eleven billion, six hundred twenty-three million, one hundred thirteen thousand, two hundred thirty-five".
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