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10213001 is a prime number
BaseRepresentation
bin100110111101…
…011010001001
3201012212121022
4212331122021
510103304001
61002522225
7152544341
oct46753211
921185538
1010213001
1158461a7
123506375
1321677c6
1414dbd21
15d6b11b
hex9bd689

10213001 has 2 divisors, whose sum is σ = 10213002. Its totient is φ = 10213000.

The previous prime is 10212967. The next prime is 10213003. The reversal of 10213001 is 10031201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10086976 + 126025 = 3176^2 + 355^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10213001 is a prime.

Together with 10213003, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10213001.

It is not a weakly prime, because it can be changed into another prime (10213003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106500 + 5106501.

It is an arithmetic number, because the mean of its divisors is an integer number (5106501).

Almost surely, 210213001 is an apocalyptic number.

It is an amenable number.

10213001 is a deficient number, since it is larger than the sum of its proper divisors (1).

10213001 is an equidigital number, since it uses as much as digits as its factorization.

10213001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 8.

The square root of 10213001 is about 3195.7786218698. The cubic root of 10213001 is about 216.9623909282.

Adding to 10213001 its reverse (10031201), we get a palindrome (20244202).

The spelling of 10213001 in words is "ten million, two hundred thirteen thousand, one".