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10213213121047 is a prime number
BaseRepresentation
bin1001010010011111001011…
…1100001010101000010111
31100011101002101100000220101
42110213302330022220113
52314313130024333142
633415515122114531
72102610641102146
oct224476274125027
940141071300811
1010213213121047
113288443604672
12118b4804aba47
13591142a48a01
14274471db575d
1512aa083b60b7
hex949f2f0aa17

10213213121047 has 2 divisors, whose sum is σ = 10213213121048. Its totient is φ = 10213213121046.

The previous prime is 10213213121003. The next prime is 10213213121063. The reversal of 10213213121047 is 74012131231201.

It is a happy number.

10213213121047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10213213121047 - 219 = 10213212596759 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10213213121077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106606560523 + 5106606560524.

It is an arithmetic number, because the mean of its divisors is an integer number (5106606560524).

Almost surely, 210213213121047 is an apocalyptic number.

10213213121047 is a deficient number, since it is larger than the sum of its proper divisors (1).

10213213121047 is an equidigital number, since it uses as much as digits as its factorization.

10213213121047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 10213213121047 its reverse (74012131231201), we get a palindrome (84225344352248).

The spelling of 10213213121047 in words is "ten trillion, two hundred thirteen billion, two hundred thirteen million, one hundred twenty-one thousand, forty-seven".